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[backport] [spark] Make spark model have the same UID with its estimator (#9022) (#9285)

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Signed-off-by: Weichen Xu <weichen.xu@databricks.com>
Co-authored-by: WeichenXu <weichen.xu@databricks.com>
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Jiaming Yuan 2023-06-11 13:18:23 +08:00 committed by GitHub
parent 3218f6cd3c
commit e882fb3262
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1 changed files with 5 additions and 1 deletions
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python-package/xgboost/spark/core.py
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@ -866,7 +866,11 @@ class _SparkXGBEstimator(Estimator, _SparkXGBParams, MLReadable, MLWritable):
result_xgb_model = self._convert_to_sklearn_model( result_xgb_model = self._convert_to_sklearn_model(
bytearray(booster, "utf-8"), config bytearray(booster, "utf-8"), config
) )
return self._copyValues(self._create_pyspark_model(result_xgb_model)) spark_model = self._create_pyspark_model(result_xgb_model)
# According to pyspark ML convention, the model uid should be the same
# with estimator uid.
spark_model._resetUid(self.uid)
return self._copyValues(spark_model)
def write(self): def write(self):
""" """